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x + 1/x = 2 x + 1/x - 2 = 0 x2 - 2x + 1 = 0 ( x - 1 )( x - 1 ) = 0 x = 1

Q: Sum of a number and its reciprocal is 2 Find the number?

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A number . . . ' x 'Its reciprocal . . . 1/xTwice its reciprocal . . . 2/xThe sum of (the number) and (twice its reciprocal) . . . x + 2/xThe equation:x + 2/x = 3Multiply each side of the equation by 'x' :x2 + 2 = 3xSubtract 3x from each side:x2 - 3x + 2 = 0Factor the left side, in order to see what's going on:(x - 1) (x - 2) = 0This is true if 'x' is either ' 1 ' or ' 2 '.x = 1The sum of the number and twice its reciprocal . . . 1 + 2/1 = 3X = 2The sum of the number and twice its reciprocal . . . 2 + 2/2 = 3

== The sum of any number and zero is that number.(2+0== 2) == the sum of any number and zero is that number. (2+0=2)

Say, find the reciprocal of 2 = 1/2 Reciprocal of 1/2 = 2

The reciprocal of 2 is 1/2 (one-half). The reciprocal of any number is 1/number. Simply stated: The reciprocal of any number is the inverse of that number. Let some number, any number, be represented by 'a'. The reciprocal of 'a' is 1/'a'.

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

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A number . . . ' x 'Its reciprocal . . . 1/xTwice its reciprocal . . . 2/xThe sum of (the number) and (twice its reciprocal) . . . x + 2/xThe equation:x + 2/x = 3Multiply each side of the equation by 'x' :x2 + 2 = 3xSubtract 3x from each side:x2 - 3x + 2 = 0Factor the left side, in order to see what's going on:(x - 1) (x - 2) = 0This is true if 'x' is either ' 1 ' or ' 2 '.x = 1The sum of the number and twice its reciprocal . . . 1 + 2/1 = 3X = 2The sum of the number and twice its reciprocal . . . 2 + 2/2 = 3

The reciprocal of a number plus the reciprocal of twice the number equals Find the number. 1/2 find the number

== The sum of any number and zero is that number.(2+0== 2) == the sum of any number and zero is that number. (2+0=2)

Say, find the reciprocal of 2 = 1/2 Reciprocal of 1/2 = 2

A number multiplied with it's reciprocal must be one. So for example if you have -(1/2), than it's reciprocal is -2.

1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.

A reciprocal is of a number is 1/number.The reciprocal of 2 is 1/2 = 0.5

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

The reciprocal of 2 is 1/2 (one-half). The reciprocal of any number is 1/number. Simply stated: The reciprocal of any number is the inverse of that number. Let some number, any number, be represented by 'a'. The reciprocal of 'a' is 1/'a'.

Let x be the positive number we're looking for. The sum of x and its reciprocal is: x + 1/x We want to find the value of x that minimizes this sum. One way to do this is to use calculus. We can take the derivative of the sum with respect to x, set it equal to zero to find the critical points, and then test those points to see which one gives the minimum value. The derivative of the sum is: 1 - 1/x^2 Setting this equal to zero and solving for x, we get: x^2 = 1 x = 1 or x = -1 (but we discard this solution since we are looking for a positive number) So, the minimum sum occurs when x = 1. Checking, we have: 1 + 1/1 = 2 This is the minimum possible value of the sum. Therefore, the positive number we're looking for is 1.

To find the reciprocal of a fraction, you turn it upside down. So the reciprocal of 1/2 is 2/1, or just 2.

The reciprocal of 2/7 is 7/2.