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No.
They cannot.
The following problem is a parabola so there is only one turning points so the answer is going to be: 2
Locate the turning point(s) for the following functions. (a) y=x3-x2 -3x + 5 3
Suppose you have a quadratic function of the form y = ax2 + bx + c where a, b and c are real numbers and a is non-zero. [If a = 0 it is not a quadratic!] The turning point for this function may be obtained by differentiating the equation with respect to x, or by completing the squares. However you get there, the turning point is the solution to 2ax + b = 0 or x = -b/2a Now, if a > 0 then the quadratic has a minimum at x = -b/2a and it has no maximum because y tends to +∞ as x tends to ±∞ . if a < 0 then the quadratic has a maximum at x = -b/2a and it has no minimum because y tends to -∞ as x tends to ±∞. You evaluate the value of y at this point. y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c = -(b2 - 4ac)/4a In either case, if the domain of the function is bounded on both sides, then the missing extremum will be at one or the other bound - whichever is further away from (-b/2a).
No.
The answer depends on the form in which the quadratic function is given. If it is y = ax2 + bx + c then the x-coordinate of the turning point is -b/(2a)
They cannot.
there is no natural way of turning green but i suppose you could pain yourself green but i wouldn't recommend it
it depends on the power of the leading coefficient, and that is not always a great indication because polynomials can have non real numbers. A factor of a polynomial is where the function crosses the x axis. If the trinomial will not factor into real numbers, then there are not any real zeros but there are still factors. Think of this one x^2+6x+14. this will not factor into real numbers, but complex solutions. But these complex solutions are factors, so the rule still holds. If the trinomial is a cubic, or at a odd power, then its a odd function, and can have one real solution. If the trinomial is squared, or any even power, its a even function and can have two real solutions. With the graph you can determine it this way: if p(x) is a polynomial function of degree n, then the graph has at most n-1 turning points. If the graph of a function P has n-1 turning points, then the degree of p(x) is at least n.
neck
Turning slotted head screws.
Polynomials of an even degree will always have either a minimum point, or a maximum point, or both.Polynomials of an odd degree may or may not have minima or maxima. If, for example, a polynomial function is simply a transformation of xn, there will be no turning points. For example:f(x) = x5 + 5x4 + 10x3 + 10x2 + 5x + 1 = (x+1)5f'(x) = 5(x+1)4There is only one solution for f'(x) = 0, which is of course x = -1. Since the range of f(x) includes all the real numbers, it follows that this solution represents a point of inflection, and not a turning point.If a polynomial of odd degree does have any turning points, it will have at least one minimum point. It cannot have maximum points only.* * * * *Polynomials of an odd degree cannot have a global maximum or minimum because if the leading coefficient is positive, it goes asymptotically from minus infinity to plus infinity and the other way around if the leading coefficient is negative.
if you consider an animal turning out to be a different color then what its suppose to be, for the better like blending in to survive
It is a turning point. It lies on the axis of symmetry.
Two.Two.Two.Two.
No, the term "turning color" is a predicate, consisting of a verb and a direct object.A predicate is the verb in a sentence and all the words that follow that pertain to that verb.The word "turning" is the present participle of the verb to "turn".The word "color" is functioning as the direct object of the verb.Example: He was embarrassed and his face was turning color.The present participle of the verb "turning" can also function as an adjective and a gerund (a verbal noun).The word "color" can function as a noun or a verb.