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Suppose you invest 1500 at an annual interest rate of 5 compounded continuously. How much will you have in the account after 4 years Round the solution to the nearest dollar.?
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What is the correct formula for compound interest?
Suppose the amount invested (or borrowed) is K, Suppose the rate of interest is R% annually, Suppose the amount accrues interest for Y years. Then the interest I is 100*K[(1 + R/100)^Y - 1]
How do you graph a solution set?
just add all the numbers I suppose and the number you get is the number you graph the solution. I suppose.
How much would 100 invested at 4 percent interest compounded continuously be worth after 7 years?
The formula for the amount received (A) when investing P after n periods where the rate per period is r% is given by:A = P(1+ r/100)nIf you have an apr (annual percentage rate) and it is applied monthly, then the rate is apr ÷ 12 applied 12n times (for n years).So going back to your question:I assume the 4% is 4% apr.So the return if the interest is applied yearly would be:A = 100 x (1 + 0.04)7~= 131.59However, you specify continuously - what exactly does "continuously" mean. Let suppose that the interest is applied monthly, then:A = 100 x (1 + 0.04/12)7 x 12~= 132.25Hmmm...we got a little more; how about more often, say daily (I'll ignore the fact of leap years and assume 365 days per year):A = 100x (1 + 0.04/365)7 x 365~= 132.31Not much more, how about hourly (still assuming 365 days/year):A = 100x (1 + 0.04/8760)7 x 8760~= 132.31(There's actually a difference, but not big enough to show in monetary terms). Going to every minute:A = 100x (1 + 0.04/525600)7 x 525600~= 132.31We seem to have hit a limit!The actual return you will get if the (100r)% apr was applied continuously for n years is:A = PernSo for 100 at 4% apr for 7 years, this is:A = 100e0.04 x 7~= £132.31
How many years will it take for an initial investment of 19000 to grow to 38500 Assume a rate of interest of 13 percent compounded daily?
13% daily is worse than any loan shark!Suppose it takes n days, then38500 = 19000*(1 + 13/100)n= 19000*(1.13)nSo 38500/19000 = 1.13nln(38500/19000) = n*ln(1.13)so that n = ln(38500/19000) / ln(1.13) = 5.78So 6 days.
How do you find the principal when all you have is the rate the time and the interest?
The answer depends on whether you are dealing with simple interest of compound interest. Suppose P = Principle R = Rate (in % per annum) T = Time (in years) I = Interest Then for simple interest: I = P*R*T/100 so that P = 100*I/(R*T) For compound interest P+I = P*(1+R/100)T so that P = I/[(1+R/100)T - 1]
Suppose you invest 1600 at an annual interest rate of 5.5 percent compounded continuously How much will you have in the account after 25 years?
balls
Suppose Betty takes out a loan for 300 at an annually compounded interest rate of 6 percent to be repaid after 5 years How much will be required to pay off the loan?
390.45
How do you work out interest accrued on spreadsheet for compound interest?
SupposeCapital invested = YAnnual Interest Rate = R%Period of investment = TThen if the interest is calculated (and compounded) n times a yeartotal value =Y*[1 + r/(100*n)]^(n*T)So interest accrued = Total value - YSupposeCapital invested = YAnnual Interest Rate = R%Period of investment = TThen if the interest is calculated (and compounded) n times a yeartotal value =Y*[1 + r/(100*n)]^(n*T)So interest accrued = Total value - YSupposeCapital invested = YAnnual Interest Rate = R%Period of investment = TThen if the interest is calculated (and compounded) n times a yeartotal value =Y*[1 + r/(100*n)]^(n*T)So interest accrued = Total value - YSupposeCapital invested = YAnnual Interest Rate = R%Period of investment = TThen if the interest is calculated (and compounded) n times a yeartotal value =Y*[1 + r/(100*n)]^(n*T)So interest accrued = Total value - Y
What is the correct formula for compound interest?
Suppose the amount invested (or borrowed) is K, Suppose the rate of interest is R% annually, Suppose the amount accrues interest for Y years. Then the interest I is 100*K[(1 + R/100)^Y - 1]
How do you graph a solution set?
just add all the numbers I suppose and the number you get is the number you graph the solution. I suppose.
Is it possible for oil to have a solution in solid or gaseous form?
I suppose that is not possible.
What is the name of the process salt solution?
I suppose that you think to the dissolution of salt in water.
How many grams of sodium fluoride are needed to make 6.3 liters of a 3.6 molar solution?
I suppose that this solution doesn't exist.
What is the end point when aluminium fluoride solution is titrated against thorium nitrate solution?
I don't know, I suppose we have to ask a chemist.
What is a chemical bond that helps control the pH of a solution?
I suppose that you think to a buffer, not bond.
Suppose that you plan on investing into an account paying simple interest The formula for simple interest is I equals Prt where I is the interest earned on a investment of P dollars at the given rate?
No. I is as described for the stated period.
Is steel a liquid solution?
At a certain temperature, Steel becomes liquid. And I suppose it is even a solution as Steel is an alloy of metals, Not only Iron alone.
