Let the number by 'm' & 'n'
Hence
m + n = 27
m - n = 7
Add; this will eliminate 'n'
Hence
2m = 34
m = 34/2 = 17
When m = 17
17 + n = 27
n = 27 - 17
n = 10
So the two numbers are 10, & 17.
35+27=62
27 and 81
12 and 15 have a sum of 27 and a difference of 3. Their LCM is 60.
27 and 13
The two equal numbers that have a sum of 54 are 27 and 27. When you add these two numbers together, you get 54. This is because the sum of two equal numbers will always be double the value of one of the numbers. In this case, 27 + 27 = 54.
The numbers are 27 and 23
The numbers are: 27 and 23
12 and 15
The answer is: 3
The numbers are 26 and 27.
forming a simultaenous equation where x+y=27 and x-y=3 you find that x=15 and y=12.
x+y=40 + x-y=14 2x =54 x=27 y=13