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Q: The larger of two numbers is nine less than four times the smaller number. If the sum of the two numbers is 76, find both numbers?

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The larger of two numbers is 8 more than 4 times the smaller if the larger number is increased by four times the smaller the result is 40. From this statement, we can calculate the values of the numbers where you get the value of the larger number to be 24 and that of the smaller number to be 4.

The larger number is 12.

12 and 28

The smaller number is 9 . You should certainly be able to handle it from there.

101 and 26

The smaller number is x. The larger number is 4x + 4. Their sum is 34. Therefore x + 4x + 4 = 34. 5x + 4 = 34. 5x = 30. x = 6. The smaller number is 6. The larger number is (4 x 6) + 4 = 28.

Generally yes, but not in all cases. The largest prime number has over 22 million digits but only two factors whereas 60 has six times as many factors.

ya i will solve this question by taking assumptions if we observe the question easily identified the larger number is greater than smaller number by 6 and one thing is the sum of two numbers is 3 times their difference from this information we clearly says sum is divided by 3 so if we take smaller number 1 larger number 7(add 6) (1+6)=3(5) and now smaller number 2 larger number 8 (2+8)=3(6) : : : take smaller number 6 larger number 12 this is the correct answer 6+12=3(6)

There can be no such integers: a smaller integer cannot be 5 times the larger number.

The sum of the numbers is 240. If one number is 5 times as big as the other then 240 must be divided by 6. 240/6 = 40. The smaller number must be this while the larger number is 5 times the size. Small number = 40 Larger number = 40 * 5 = 200

a=3b

4x - x = 36 so x = 12 and the other number is 48.

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