15 cm + 7 cm = 22 cm
3 inches is longer than 7 cm.
15-7=8 15=7+8
8 = 15 - 7 8 = 8 Yes it is an equation.
7 cm is longer than 68 mm.
15 cm and 8cm Solved with the help of Pythagoras' theorem and the quadratic equation formula.
Let the sides be x and x-7 So using Pythagoras: x2+(x-7)2 = 172 => 2x2-14x-240 = 0 Solving the quadratic equation gives x a positive value of 15 Therefore sides are: 15 and 15-7 = 8 Perimeter: 17+15+8 = 40 cm
It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15
Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm
3.5 cm is 5 times as long as 7 mm, and 4 times longer than 7 mm.
7 cm * 7 cm * 3.14 * 15 cm = 2307.9 cm3
Suppose the shorter side is x cm.Then the longer side is x + 3.5 cm. Therefore the perimeter is 2*(x + x + 3.5) = 4x + 7 cm. Now 4x + 7 = 67 so that 4x = 60 and x = 15 and then x + 3.5 = 18.5 Therefore the sides of the rectangles are 15 cm and 18.5 cm.
Let the shortest side be x cm, so that the longest side is 2x cm, and the third side is x + 7 cm. Since the perimeter of the triangle is 39 cm we have:x + 2x + x + 7 = 394x = 32x = 8Thus, the lengths of the sides are 8 cm, 15 cm, and 16 cm.