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Name the length L & the width W ,then:

L x W = 60

L = 4 + W

Solve the system by substituting the value of L from the second equation in the first one.

( 4 + W )X W = 60

4W + W^2 = 60

W^2 + 4W - 60 = 0

W = 6 accepted

& W = -10 rejected

Now,solve for L :

L = 4 + 6 = 10

So, the length is 10 feet & the width is 6 feet

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Q: The area of a rectangle is 60 in 2 The length is 4 inches greater than the width Find the length?
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