Name the length L & the width W ,then:
L x W = 60
L = 4 + W
Solve the system by substituting the value of L from the second equation in the first one.
( 4 + W )X W = 60
4W + W^2 = 60
W^2 + 4W - 60 = 0
W = 6 accepted
& W = -10 rejected
Now,solve for L :
L = 4 + 6 = 10
So, the length is 10 feet & the width is 6 feet
7
Any length greater than six.
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
105 = 7 x 15.
LENGTH and WIDTH
7
The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches
Any length greater than six.
10 in. A+LS
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
if the length is 36 on a rectangle then what is the width of the rectangle
Length 7 inches and width 4 inches because 7*4 = 28 square inches
The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width
if a rectangle is 450 square inches and the length is 24 inches what is the width?
15 x 7 = 105...
105 = 7 x 15.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.