12
The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.The average of the first n even numbers is n+1, so 101.
The sum of the first 10 natural numbers is 51, with an average of 5.1
The average is 10. You will find that the average when adding together the first n odd numbers is always equal to n.
The average of the first 91 natural numbers can be calculated using the formula for the average of the first ( n ) natural numbers, which is given by ( \text{Average} = \frac{n(n + 1)}{2n} ). For ( n = 91 ), the sum of the first 91 natural numbers is ( \frac{91 \times 92}{2} = 4186 ). Dividing this sum by 91 gives an average of ( \frac{4186}{91} = 46 ). Therefore, the average of the first 91 natural numbers is 46.
The answer is one million (the average of the first n odd numbers is always n.)
To find the average of all seven numbers, we first calculate the total for the first four numbers. Since their average is 15, their total is (4 \times 15 = 60). For the last three numbers, with an average of 8, their total is (3 \times 8 = 24). Therefore, the total of all seven numbers is (60 + 24 = 84), and the average of all seven numbers is ( \frac{84}{7} = 12).
First 3 composite numbers: 4+6+8 = 18 and 18/3 = 6 which is the average number
38.5
25.5
7.4
50.5
The Average number is the average of the numbers you're trying to find. To find the average number, you must add up all the numbers first and then divide by the number of numbers. Trust Point Me if this helped, Thanks!