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Q: The circle below is centered at the point (3-4) and has a radius of length 3.?
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When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?

Equation of the circle: (x+1)^2 +(y+3)^2 = 25


Write missing expression in the program below which would print the area of circle r int input Enter the circle radius?

Area of any circle = pi*radius squared


What instrument measures the area of a circle?

A scale ie required to measure the area of a circle. We need to measure the radius of that Circle and then we can put this radius valve in below mwntioned formula & can calculate the area. A=3.14*r*r where r is radius in Cm. A is are in cm square. Hemant gautam +919099921329


Formula for finding the radius of a circle?

1. The radius of a circle is half of its diameter.2. The radius can also be calculated from its circumference (C).Method: Divide the circumference by Pi, this will give you the diameter. Then divide the diameter by 2 to get the radius (r).Formula: r = C/2π3. The radius can also be calculated from the area of the circle. Area = π x r2So, divide area by Pi, then the radius will be the square root of the answer.For more information, try the Related links below.


What is the length of the tangent line from the point 8 2 to a point where it touches the circle of x2 plus y2 -4x -8y -5 equals 0?

The tangent of a circle is perpendicular to the radius to the point of contact (Xc, Yc).The point (Xg, Yg), the centre of the circle (Xo, Yo) and the point of contact of the tangent (Xc, Yc) form a right angle triangle.The leg from the point (Xg, Yg) to the point of contact (Xc, Yc) is the required lengthThe leg from the centre of the circle (Xo, Yo) to the point of contact (Xc, Yc) has length equal to the radius (r) of the circleThe hypotenuse is the length between the point (0, 0) and the centre of the circle (Xo, Yo).To solve this:Find the centre (Xo, Yo) of the circle, and its radius r;Use Pythagoras to find the length between the point (Xg, Yg) and the centre of the circle (Xo, Yo);Use Pythagoras to find the length between the point (Xg, Yg) and the point of contact (Xc, Yc) of the tangent - the required length.Hint: a circle with centre (Xo, Yo) and radius r has an equation of the form:(x - Xo)² + (y - Yo)² = r²Have a go at solving it now you know how, before reading the solution below:------------------------------------------------------------------------------Circle:x² + y² - 4x - 8y - 5 = 0→ x² - 4x + y² - 8y - 5 = 0→ (x - (4/2))² - (4/2)² + (y - (8/2))² - (8/2)² - 5= 0→ (x - 2)² - 4 + (y - 4)² - 16 - 5 = 0→ (x - 2)² + (y - 4)² = 25 = radius²→ Circle has centre (2, 4) and radius √25 = 5Line from centre of circle (2, 4) to the given point (8, 2):Using Pythagoras to find length of a line between two points (x1, y1) and (x2, y2):length = √((x2 - x1)² + (y2 - y1)²)To find length between given point (8, 2) and centre of circle (2, 4)→ length = √((2 - 8)² + (4 - 2)²)= √((-6)² + 2²)= √40Tangent line segment:Using Pythagoras to find length of tangent between point (8, 2) and its point of contact with the circle:centre_to_point² = tangent² + radius²→ tangent = √(centre_to_point² - radius²)= √((√40)² + 25)= √65≈ 8.06

Related questions

What is the equation of The circle below is centered at the point (-2 -3) and has a radius of length 7.?

Equation of circle: (x+2)^2 +(y+3) = 49


When The circle below is centered at the point (3 2) and has a radius of length 7. What is its equation?

Equation of circle: (x-3)^2 +(y-2)^2 = 49


The circle below is centered at the point (1, 2) and has a radius of length 3 What is its equation?

Equation of the circle: (x+1)^2 +(y+3)^2 = 25


When The circle below is centered at the point (-1 -3) and has a radius of length 5. What is its equation?

Equation of the circle: (x+1)^2 +(y+3)^2 = 25


The circle below is centered at the point (1 2) and has a radius of length 3. What is its equation?

(x-1)^2 + (y-2)^2 = 3^2


When The circle below is centered at the point (-3 -4) and has a radius of length 2. What is its equation?

The equation is: (x+3)^2 + (y+4)^2 = 4


The equation for the circle below is x2 plus y2 16. What is the length of the circle's radius?

4


The equation for the circle below is x2 plus y2 81. What is the length of the circle's radius?

9 (APEX)


The blue segment below is a radius of O. What is the length of the diameter of the circle?

the andser is 9


The blue segment 7 point 4 below is a diameter of O What is the length of the radius of the circle?

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What is the formula for the radius of a circle?

Divide the diameter by 2 to get the radius. See related questions below.


In circle A below the radius is 3 and BC is tangent to the circle. Find BC?

Not enough information has been given to find the tangent BC but it will be perpendicular or at right angles to the radius of the circle.