m3 kg-1 s-2.
Cavendish measured the gravitational constant "G".
g, the force of the Earth's gravitational attraction, is not a constant.
Well, let's see:Force of gravity = G M1 M2 / R2So G = (force) x (distance)2 / (mass)2 = (M L / T2) x (L2) / (M2) = (M L3) / (M2 T2) =(Length)3 (Mass)-1(Time)-2
It is m3kg-1s-2
Gravitational constant was determined by lord Henry cavendish in 1798 using a torsion balance .....G=6.67 *10^-9
Cavendish measured the gravitational constant "G".
g, the force of the Earth's gravitational attraction, is not a constant.
There is no evidence to suggest that the gravitational constant 'G' is not the exact same number everywhere in the universe.
The force between two massess m1 and m2 is given by F = G m1 m2 / r^2 G is gravitational constant. r is the distance between the masses.
Acceleration due to gravity in the vicinity of a mass 'M' is A = G M / R2 A = the acceleration G = gravitational constant M = mass of the mass R = distance from the center of the mass 'M'
gravitational potential means apply force on a object of mass m and opposite to the gravitational force and take the object to one point to another point. gravatiotanal potential = L-1
Well, let's see:Force of gravity = G M1 M2 / R2So G = (force) x (distance)2 / (mass)2 = (M L / T2) x (L2) / (M2) = (M L3) / (M2 T2) =(Length)3 (Mass)-1(Time)-2
Force gravitational = (mass of the object)(the gravitational constant) F=mg "g" is the gravitational constant, it is equal to 9.8 m/s^2
The gravitational constant denoted by letter G, is an empirical physical constant involved in the calculation(s) of gravitational force between two bodies
An upper case (capital) G.
Formula for Gravitational potential is - G M / r Here G is universal Gravitation constant, M - mass of the planet and r is the distance of the point from the centre of the planet. The unit is J/kg If potential energy is needed then the potential is to be multiplied by the mass m. So gravitational potential energy = - G M m / r So the unit would be J (joule)
It is m3kg-1s-2