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-- Square the difference between their 'x'-values. -- Square the difference between their 'y'-values. -- Add the two squares. -- Take the square-root of the sum. The result is the distance between the points.
The absolute value of the difference.
(Distance between the points)2 = (difference of the two x-values)2 + (difference of the two y-values)2
-- take the difference between the 'x' values of the two points; square it -- take the difference between the 'y' vales of the two points; square it -- add the two squares together -- take the square root of the sum The result is the distance between the two points.
A straight line is the shortest distance between two points, a line is the delineation of a connection between two or more points.
The distance between two points is Square root of [ (difference in their 'x' coordinates)2 + (difference in their 'y' coordinates)2 ]
-- Square the difference between their 'x'-values. -- Square the difference between their 'y'-values. -- Add the two squares. -- Take the square-root of the sum. The result is the distance between the points.
The absolute value of the difference.
(Distance between the points)2 = (difference of the two x-values)2 + (difference of the two y-values)2
The slope is the change in distance between any two points divided by the change in time between them.
-- take the difference between the 'x' values of the two points; square it -- take the difference between the 'y' vales of the two points; square it -- add the two squares together -- take the square root of the sum The result is the distance between the two points.
displacement is the vector quantity and the distance is scalar quantity, displacement is the shortest distance between two points.
The distance between any two points on a number line is the absolute value of the difference of the coordinates.
A straight line is the shortest distance between two points, a line is the delineation of a connection between two or more points.
In 2-dimensional space, it is the difference between their y-coordinates, in 3-dimensional space, it is the difference between their z-coordinates.
The difference in the y coordinates would be your vertical separation.
The distance between the points can be calculated by using the difference in the x coordinates, the difference in the y coordinates and Pythagoras. distance = sqrt((difference_in_x_coords)2 + difference_in_y_coords)2) So for the points (-1, 1) and (1, -1) the distance between them is: sqrt((-1 - 1)2 + (1 - -1)2) =sqrt(22 + 22) =sqrt(4 + 4) = sqrt(8) ~= 2.83