The sum of the first 60 consecutive odd numbers is 3,600.
900
31 + 59 = 90
The sum of the numbers from 1 to 60 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the last number in the series. For the numbers 1 to 60, ( n = 60 ). Thus, the sum is ( S_{60} = \frac{60(60 + 1)}{2} = \frac{60 \times 61}{2} = 1830 ). Therefore, the sum of the numbers from 1 to 60 is 1830.
Their sum is -12
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
Divide 60 by the first six counting numbers.
900
31 + 59 = 90
The sum of the numbers from 1 to 60 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the last number in the series. For the numbers 1 to 60, ( n = 60 ). Thus, the sum is ( S_{60} = \frac{60(60 + 1)}{2} = \frac{60 \times 61}{2} = 1830 ). Therefore, the sum of the numbers from 1 to 60 is 1830.
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
The sum of all prime numbers between 60 and 75 is 272
Their sum is -12
The answer to what is the sum of the first positive even numbers is 930. It doesn't mean that you add all the even numbers up until you reach the number 30. In fact, since you have to get the sum of the even numbers, you have to add all even numbers until you get to the number 60.
The sum of the first 60 positive integers is 1830.