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The sum of the numbers from 1 to 60 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the last number in the series. For the numbers 1 to 60, ( n = 60 ). Thus, the sum is ( S_{60} = \frac{60(60 + 1)}{2} = \frac{60 \times 61}{2} = 1830 ). Therefore, the sum of the numbers from 1 to 60 is 1830.

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3mo ago

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What is the answer when you add all numbers from 40 to 60?

The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050


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The sum of the counting numbers from 1 to 60 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n}{2} \times (a + l) ), where ( n ) is the number of terms, ( a ) is the first term, and ( l ) is the last term. Here, ( n = 60 ), ( a = 1 ), and ( l = 60 ). Plugging in these values, the sum ( S_{60} = \frac{60}{2} \times (1 + 60) = 30 \times 61 = 1860 ). Therefore, the sum of the counting numbers from 1 to 60 is 1860.


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