Want this question answered?
It is an increasing odd function.
No. By definition, a function has a single unique value for every value passed into it. The equation given here describes a circle, which can not be rearranged to meet this condition.
The function f(x) = 3x + 2 can take any real value, so the question does not seem to make any sense.
The function that is given has a constant value and therefore, its slope is 0.
You pass arguments to functions because that is how you tell the function what you want it to do. If you had, for instance, a function that calculated the square root of something, you would pass that something as an argument, such as a = sqrt (b). In this case sqrt is the function name, b is passed as its argument, and the return value is assigned to a.
It is an increasing odd function.
Absolutely. Indeed, any function (user-defined or built-in) that does not return a value is not really a function, it is simply a procedure.
use the _itoa function
By returning a value. Or using type 'void'.
The answer is below!
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It is 4.
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True - A C++ constructor cannot return a value.
B- It is a many-to-one function
You can tell if an equation is a function if for any x value that you put into the function, you get only one y value. The equation you asked about is the equation of a line. It is a function.
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