0
Possibly under certain conditions, but not generally.
Consider a nonmeasurable set A, and define
f(x) = 1 if x in A
0 otherwise.
Then {1} is certainly measurable but the inverse image
{x | f(x) = 1} = A is not measurable.
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Is a constant function on a measurable set is measurable?
Yes.
What are operations undo each other or the additive inverse?
Inverse operations. Additive inverse is not one operation but they are elements of a set.
What is inverse in algebra?
Given a set and a binary operation defined on the set, the inverse of any element is that element which, when combined with the first, gives the identity element for the binary operation. If the set is integers and the binary operation is addition, then the identity is 0, and the inverse of an integer k is -k. If the set is rational numbers and the binary operation is multiplication, then the identity element is 1 and the inverse of any member of the set, x (other than 0) is 1/x.
Distinguish between measurable variable and non-measurable variables of a product?
One way is to check whether the pre-image of the product is sigma-algebra. Please list an example to clarify your question.
How is the additive inverse important?
It gives closure to the set of real numbers with regard to the binary operation of addition. This makes the set a ring. The additive inverse is used, sometimes implicitly, in subtraction.
What select inverse does in Photoshop?
Select Inverse will invert selection, if you have selected circle in the middle of the image, inverse will make that only circle is not selected but everything else in the image.
Is a constant function on a measurable set is measurable?
Yes.
If constant function is measurable then is it necessary that domain is measurable?
yes.since this functin is simple .and evry simple function is measurable if and ond only if its domain (in this question one set) is measurable.
What is definition of pre-image in math?
The definition of pre-image in math:For a point y in the range of a function ƒ, the set of points x in the domain of ƒ for which ƒ(x) = y. For a subset A of the range of a function ƒ, the set of points x in the domain of ƒ for which ƒ(x) is a member of A. Also known as inverse image.
What are operations undo each other or the additive inverse?
Inverse operations. Additive inverse is not one operation but they are elements of a set.
What is inverse in algebra?
Given a set and a binary operation defined on the set, the inverse of any element is that element which, when combined with the first, gives the identity element for the binary operation. If the set is integers and the binary operation is addition, then the identity is 0, and the inverse of an integer k is -k. If the set is rational numbers and the binary operation is multiplication, then the identity element is 1 and the inverse of any member of the set, x (other than 0) is 1/x.
What is the difference between multiplicative inverse and additive inverse?
The multiplicative inverse of a non-zero element, x, in a set, is an element, y, from the set such that x*y = y*x equals the multiplicative identity. The latter is usually denoted by 1 or I and the inverse of x is usually denoted by x-1 or 1/x. y need not be different from x. For example, the multiplicative inverse of 1 is 1, that of -1 is -1.The additive inverse of an element, p, in a set, is an element, q, from the set such that p+q = q+p equals the additive identity. The latter is usually denoted by 0 and the additive inverse of p is denoted by -p.
What is high set and low set current setting?
The low-set stage is a current with a definite time or inverse-time operation. The high-set stage has a definite time characteristic only without the inverse-time operation.
Distinguish between measurable variable and non-measurable variables of a product?
One way is to check whether the pre-image of the product is sigma-algebra. Please list an example to clarify your question.
What number has no multiple inverse?
On the set of all real numbers ZERO has no multiplicative inverse. For other sets there may be other numbers too, so please define your set!
What is the solution set for an identity?
It depends on what identity you are talking about whether its multiplicative inverse to additive inverse i mean you have to be more specific
How is the additive inverse important?
It gives closure to the set of real numbers with regard to the binary operation of addition. This makes the set a ring. The additive inverse is used, sometimes implicitly, in subtraction.
