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Q: The length of a rectangle is two times its width. If the perimeter of the rectangle is 48 what is its area?

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2 times (length + width)

The area is the length times the width. The perimeter is two times the length plus two times the width.

perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.

The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)

Width: 8.5 Length: 25.5

Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.

2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter

Area is length times width, perimeter is twice the sum of length and breadth.

call width x so length is 3x perimeter is (2*length)+(2*width) so perimeter is 8x

If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length

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