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Let the length be (2x+1) and the width be x:

length*width = area

(2x+1)*x = 21 square miles

2x2+x-21 = 0

Solving the above quadratic equation works out as:

x = -7/2 or x = 3 it must be the latter because dimensions can't be negative.

Therefore: length = 7 miles and width = 3 miles

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Q: The length of an airport is 1 mile more than twice the width the area is 21 square miles identify the legth and width of the airport?
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