The perimeter can be written as 2x + 2y = P where the x is length and y is width
we know that y = x + 58 so 2y = 2x + 116
2x + 2x + 116 = 260
4x=148
x=37
37+58=95
y=95
Length + width = half perimeter = 100". Length is 98", width is 2"
38 x 44
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in
Since the length exceeds the width by 39 inches, if x is the width, then you can express the length as x + 39. Now, use the formula for the perimeter of a rectangle, replacing known values: perimeter = 2(length + width) 234 = 2(x + 39 + x) Solving this for "x" will result in the width; add 39 to get the length.
Do-it-in-your-head method:Length + width is half the perimeter, ie 76 inches;76 - 36 = 40;Half of 40 is 20: this is the width;20 + 36 = 56: this is the length.Job done.
The perimeter is all the sides added together so it would Be 3+3+7+7 the perimeter is 20
we know,perimeter of rectangle = 2 * ( l+b) perimeter= 2 *(45+30) = 2 * 75 =150 cm
The perimeter is 60 inches
Suppose width = Wthen length L = W + 36 therefore perimeter, P = 2*(L + W) = 2*(W + 36 + W) = 4W + 72 = 140 Therefore 4W = 68 => W = 17 inches and so L = 17 + 36 = 53 inches.
The length of a rectangle is 8 inches. The width of the rectangle is 4 inches. What is the perimeter of the rectangle in inches?
If the side length is 7, the perimeter is 35.