1 x 12
2 x 6
3 x 4
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
A rectangular prism has 12 edges with rectangles and squares for faces
16 1x1 rectangles + 12 2x1 rectangles + 8 3x1 rectangles + 4 4x1 rectangles + 12 1x2 rectangles + 9 2x2 rectangles + 6 3x2 rectangles + 3 4x2 rectangles + 8 1x3 rectangles + 6 2x3 rectangles + 4 3x3 rectangles + 2 4x3 rectangles + 4 1x4 rectangles + 3 2x4 rectangles + 2 3x4 rectangles + 1 4x4 rectangle. A Grand Total of: 100 squares and rectangles. OR: A rectangle is formed by 2 horizontal lines and 2 vertical lines. There are 5 horizontal and 5 vertical lines so the number of rectangles is 5C2 * 5C2 = 10 * 10 = 100
Each rectangle has four sides. Therefore, for four rectangles, you would multiply the number of rectangles by the number of sides per rectangle: 4 rectangles × 4 sides/rectangle = 16 sides. Thus, the total number of sides of four rectangles is 16.
There are infinitely many such rectangles.
if x is the prime number, there will be an infinite number of rectangles of dimension (1*x)
You can't. There are an infinite number of possible rectangles with a given area.
1 x 44 2 x 22 4 x 11
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Thee different rectangles with an area of 12 square units are 3 by 4, 2 by 6 and 1 by 12.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
Number of factor pairs = number of rectangles