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restated this question using angles a,b,c:

b=4a

c=a+b+40

a+b+c=180 (since all triangles are 180 degrees)

find b

c=a+4a+40

c=5a+40

a+4a+(5a+40)=180

10a=140

a=14

b=4(14)=56 (answer to your question)

c=14+56+40=110

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Q: The second angle of a triangle is 4 times as large as the first the third angle is 40 degrees more than the sum of the other two angles find the measure of the second angle?
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