The square root of 94 is an irrational number
The square root of 8836 is 94.
The square root of 94 would lie between 9 (9x9=81) and 10 (10x10=100).
Yo no se
No, square numbers are numbers which have a whole square root. 1x1=1 2x2=4 3x3=9 4x4=16 5x5=25 6x6=36 7x7=49 8x8=64 9x9=81 10x10=100 94 is a square number, although its square root wouldn't be a whole number √94 = 9.6954
It's perfectly simple: This was as near as i could get. 9.6953597148326580281488811508453 :]
Easy way, factoring under the radical. Sqrt(944) Sqrt(942 * 942) 94Sqrt(942) 94 * 94 = 8836 ----------
The square root of the square root of 2
Let the coefficient by 'x' Hence its square root is x^(1/2) or x^(0.5) Then the square root again is [x^(1/2)]^(1/2) Third time over {[x^(1/2)]^(1/2)}^(1/2) Now the rules of indices are [x^(n)[^(m) = x^(nm) When terms are 'nested' , multiply together. Also x^(n) X x^(m) = x^(n+m) x^)n) / x^(m) = x^(n-m) However, the first rule (nesting) applies in this case, when you multiply the indices together/ Hence x^(1/2 X 1/2 X 1/2) = x^(1/8) , Which is the 8th root.!!!!!
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There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)
It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.