Q: The sum of 20 and the sum of 3?

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[2 + (-20)] + 3

20 x 3 = 60 20 + 3 = 23

17 and 3 = 20

20 x 3 = 60 (which is the same as the sum: 20 + 20 + 20 = 60)

the sum would be 1/4 + 3/5 = 5/20 + 12/20 = 17/20

20 = 3 + 8 + 9

The appropriate equation is: 5*(-3 + N) = -20

71

3 + 17 = 20

6*(3+20) = 138

43

It is: 3+17 = 20

you need two numbers to get a sum. just -20 cannot be used for a sum.

4/20 + 15/20 = 19/20

7+3+10 = 20

Average = sum(X)/n = 60/3 = 20

You can list them out and add them up: 3 + 13 + ... + 193 {20 items}, or you can recognize the sequence: (n = 0..19) of (n*10 + 3), the sum would be 20*3 + 10*Sum[(n=0..19) of just n], which is 20*3 + 10*[190] = 60 + 1900 = 1960. If you add up the column of numbers, you get the same result.

7/20 + 3/9 = 7/20 + 1/3 = 21/60 + 20/60 = 41/60

19, 20, 21

3 and 17

20 +30 + 50

To test whether a number is divisible by 3, the sum of its digits must also be divisible by 3. In this instance, the sum of the digits of 8264 is equal to 20. Therefore, since 20 is not divisible by 3, nor is 8264.

The sum of 20 and 110 is 130.

7+3=10 17+3=20 17+13=30

1,4,5

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