3*N + 12 = 63
or
3*(N + 12) = 63
From the wording, the first is more likely but it gives rise to a fractional solution. If you are at a stage where you are learning to generate such equations, fractional answers are less likely.
It is 63.
63 x 12 = 756
One number is 63 and the other is 21.
81.
The numbers are 21 and 63.
Let the numbers be 'n' & '3n' Hence their sum is n + 3n = 84 4n = 84 n = 21 & 3n = 63 ( 3 x 21)
The sum of 36 plus 63 can be expressed as a product by first calculating the sum, which is 99. This can be factored and expressed as a product of its prime factors: (99 = 9 \times 11), or as (3^2 \times 11). Thus, the expression for the sum of 36 and 63 as a product is (9 \times 11).
51
== == 138/2=69 One number will have to be bigger than this and one will be smaller. 12/2=6 69+6=75 69-6=63 63+75=138 75-63=12
75
2x+63=191 2x = 128 x = 64
Then the number is 21 because 3 times 21 = 63