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First solve the inequality for x. The sum of 6 and twice a number (the unknown, represented by the variable x) multiplied by 3 translates to this expression algebraically: 3(2x + 6). This product is greater than or equal to 66. Expand the multiplication to: 6x + 18, which is greater than or equal to 66. Then subtract 18 from both sides to get: 6x is greater than or equal to 48. Then divide both sides by 6 to get: x is greater than or equal to 8. If x is greater than or equal to 8, then x could be 8 or 9 or 10, etc., any number from 8 on up into infinity! The smallest possible value for x given these constraints is 8.

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Q: The sum of 6 and twice a number is multiplied by three This product is greater than or equal to 66 What is the smallest value possible for this number?
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The sum of 6 and twice a number multiplied by three This product is greater than or equal to 66 What is the smallest value possible for this number?

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