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No; 20 is an abundant number. S = {1, 2, 4, 5, 10} is the set of all positive divisors of 20, excluding itself. The sum of these divisors = 1+2+4+5+10=22 which is greater than 20. Therefore 20 is an abundant number, not a deficient number. When the sum exceeds the number, the number is abundant. When the sum equals the number, the number is perfect. When the sum is less than the number, the number is deficient.

It is: 5+15 = 20

1

17 and 3 = 20

A single number cannot have a sum or a product - a sum or product is used to compare two or more numbers.

As the 20 is a whole number and the rest is a decimal number, the answer is: 20.000000001

2.5

The sum of a single number is the number itself. But usually the word "sum" is used for adding more than just one number.

If your equation is X+60=4(X) X=20 20+60=4(20) 80=80 Hope this helps.

4(x + 20)

13 & 7

2

-20 because -20 + 36 = 16

31.

5

-16

you will get an even # for a answer like 2+2=4 20+20=40

10 < x + 5 < 20

The sum of the five odd numbers between 10 and 20 is: sum = 5 x (11 + 19) / 2 = 75.

The larger number is 20.

14

An infinite number of ways.

The number 28 is a perfectly reasonable number. The sum of the digits of several numbers is 10. 19 for instance

Let the unknown number be n.Then 20 + n = 30 : Subtract 20 from both sides gives :-20 - 20 + n = 30 - 20 : n = 10

you need two numbers to get a sum. just -20 cannot be used for a sum.