4/5*(-20+5)
In any division sum, such as 5 / 20, the second number is called the divisor.
20 + 5 = 25
The sum of the five odd numbers between 10 and 20 is: sum = 5 x (11 + 19) / 2 = 75.
20+x
No; 20 is an abundant number. S = {1, 2, 4, 5, 10} is the set of all positive divisors of 20, excluding itself. The sum of these divisors = 1+2+4+5+10=22 which is greater than 20. Therefore 20 is an abundant number, not a deficient number. When the sum exceeds the number, the number is abundant. When the sum equals the number, the number is perfect. When the sum is less than the number, the number is deficient.
4/5*(-20+5)
(x+5)/4
The appropriate equation is: 5*(-3 + N) = -20
10 < x + 5 < 20
In any division sum, such as 5 / 20, the second number is called the divisor.
The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.
20/5 = 4. You can treat the fraction as a division sum.
5
20 5 times 4= 20 5+4=9
The two numbers that solve this problem are 5 and 15. The sum of 5 and 15 is equal to 20, and 15 is indeed 3 times 5.
20 + 5 = 25