Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n
Subtract 2n from each side: n + 3 = 13
Subtract 3 from each side: n = 10
Job done.
I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.
x=2, 3, 4...
43
3x + 6y = 47 6y = -3x + 47 y = -3x/6 + 47/6 y = (-3x + 47)/6 Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.
what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.
9 and 11.
The six consecutive integers greater than -7 are: -7, -6, -5, -4, -3, -2
x + (x+1) + (x+2) ≥ 42 3x + 3 ≥ 42 3x ≥ 39 x ≥ 13 so the integers must be 13, 14, 15 or any other set of consecutive integers where the smallest is greater than 13 (such as 17, 18, 19 or 231, 232, 233)
greater
The LCM of consecutive integers is their product. Consecutive integers will not both be multiples of seven.
The GCF of two consecutive numbers is always 1. The GCF of any set of numbers can't be greater than the smallest of the differences between the numbers.
2^30
The integers are the sqare root of 121 and 81 to the 2/4 power.
3 and 4
6 and 8
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
3 odd integers must total an odd number. 3 consecutive odd integers must total a multiple of 3. The lowest number greater than 162 which satisfies these requirements is 165, ie 53 + 55 + 57