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Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n

Subtract 2n from each side: n + 3 = 13

Subtract 3 from each side: n = 10

Job done.

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Q: The sum of three consecutive integers is 13 greater than twice the smallest of the three integersfind the integer?
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What are three consecutive integers that equal 171?

I'm assuming this is supposed to say: "What are three consecutive integers that add together to equal 171?"This could also be "What are three consecutive integers that multiply together to equal 171?"I will do both.For the addition caseThink of "three consecutive integers" as the expressions x, x+1, and x+2. For any value of x, these three expressions will give that number, the number that is one greater than it, and the number that is two greater than it. So, the expression x+(x+1)+(x+2) is the general sum of three consecutive integers. Also possible is the expression x+(x-1)+(x-2), which are still three consecutive integers. So, this is a simple equation:x+(x+1)+(x+2)=171x+x+1+x+2=1713x+3=1713x=168x=168/3x=56Since x=56, x+1=57 and x+2=58So the three numbers are 56,57,and 58You can check this answer by adding the three numbers together. I'll bet they equal 171.For the multiplication case:Refer to the explanation for the addition case, but instead of the end expression being x+(x+1)+(x+2), it is now the multiplication of the three integers, meaning the expression is (x)(x+1)(x+2), so we get: (x)(x+1)(x+2)=171(x)(x2+3x+2)=171x3+3x2+2x=171I'll admit right now I don't know a simple way to solve this equation, which hints to me that addition was the intent of the question, but this equation can be solved by plotting the equationsy=x3+3x2+2xy=171and finding their point(s) of intersection. The value comes out to be approximately 4.6106, which means that the numbers 4.6106, 5.6106, and 6.6106 will multiply to equal approximately 171 (but not exactly). No exact answer is really possible here.


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Does the equation 3x plus 6y equals 47 have a solution in which x and y are both positive integers?

3x + 6y = 47 6y = -3x + 47 y = -3x/6 + 47/6 y = (-3x + 47)/6 Since we are looking for positive integer, 3x (x > 0) cannot be greater than 47, the possibilities of the numerator are 42, 36, 24, 18, 12, and 6, so that - 3x must be -5, -11, -23, -29, -35, and -41. Since any of them are not multiples of -3, we can not find any pair of positive integers that satisfy the equation. So x and y cannot be both positive integers.


What is C Cx plus 2y x plus y greater or equal to 8 x greater or equal to 3 y greater or equal to 0?

what is c, x + 2y, x+y equal to or greater than 8, x equal to or greater than 3, y equal to or greater than 0.

Related questions

What are the two smallest consecutive odd integers whose sum is greater than 17?

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The sum of three consecutive integers is no less than 42. Find the integers.?

x + (x+1) + (x+2) ≥ 42 3x + 3 ≥ 42 3x ≥ 39 x ≥ 13 so the integers must be 13, 14, 15 or any other set of consecutive integers where the smallest is greater than 13 (such as 17, 18, 19 or 231, 232, 233)


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What is the greatest common factor of two consecutive numbers?

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