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Q: The sum of two natural numbers is 6 and their LCM is 4 what are the numbers?

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The numbers are 34 and 51, which have a sum of 85 and their LCM is 102, the multiple of the highest power of their prime factors 2, 3, 17.

14 and 21 have a sum of 35 and an LCM of 42

16 and 12 how did you get it

16 and 24

This doesn't work. The LCM of a pair of numbers has to be equal to or larger than the largest number of the pair. If one of the numbers is 60, the other is 120. 60 and 120 have a GCF of 60, not an LCM.

Their product.

16 and 3

4 and 6

16 and 3

16 and 3

60 and 36

40 and 50

How about: 18 and 24

40 and 50

If the question is asking for the sum of natural numbers between two members of N, then you will have to add all the natural numbers between the two numbers (excluding the actual two numbers). For example, if they ask you to calculate the sum between 2 and 5, your answer should be 3+4=7.

Yes.

HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .

There aren't two prime numbers whose LCM is 90.There aren't two prime numbers whose total is 23.Other than that...The two numbers you are looking for are 5 and 18, but only one of them is prime.

Yes.natural numbers are closed under multiplication.It means when the operation is done with natural numbers in multiplication the sum of two numbers is always the natural number.

You need at least two numbers to find an LCM. Factors of 90 that total 23 when added are 18 and 5.

It's redundant. The LCM of two natural numbers is the smallest integer solution. It's the smallest positive integer that all the members of a given set of numbers will divide into evenly with no remainder.

For this you will need a couple of helper algorithms. The first is the GCD (greatest common divisor) which is expressed as follows:procedure GCD (a, b) isinput: natural numbers a and bwhile ab doif a>blet a be a-belselet b be b-aend ifend whilereturn aThe second algorithm is the LCM (least common multiple) of two numbers:procedure LCM (a, b) isinput: natural numbers a and b return (a*b) / GCD (a, b)Now that you can calculate the GCD and LCM of any two natural numbers, you can calculate the LCM of any three natural numbers as follows:procedure LCM3 (a, b, c) isinput: natural numbers a, b and c return LCM (LCM (a, b), c)Note that the LCM of three numbers first calculates the LCM of two of those numbers (a and b) and then calculates the LCM of that result along with the third number (c). That is, if the three numbers were 8, 9 and 21, the LCM of 8 and 9 is 72 and the LCM of 72 and 21 is 504. Thus the LCM of 8, 9 and 21 is 504.

The LCM of two numbers is sometimes the product of the two numbers.

12 and 15 have a sum of 27 and a difference of 3. Their LCM is 60.

1+2=3