x + y = 14
3x + 2y = 33
x = 5
y = 9
12 and 28
The numbers are: 3 and 12
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
3x = y-1x + y = 29From the first equation, y = 3x+1Plugging into the second equation:x + 3x + 1 = 294x+1=294x=28x=7plugging that into the second equation,7 + y = 29y = 223(7)=(22)-121 = 21, and the first equation checks as well. ■
This is a set of three numbers. It is NOT an equation. There is nothing missing from a non-existent equation.
that is the dumbest question ever
a=3b
13 and 6
The larger number is 12.
The numbers are: 7 and 13
12 and 28
The numbers are: 3 and 12
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
101 and 26
Let X be the larger number and Y be the smaller number. So, X + Y = 2X - 4 and X - 3Y = -20 (1) Rearrange the first equation to get the variables to one side: X - 2X + Y = -4 -X + Y = -4 (2) Next solve simultaneously with the other equation. Add equations together to eliminate X. -X + Y = -4 X - 3Y = -20 ------------------- -2Y = -24 Y = 12, and substituting this value into the first equation and solve for X to get X = 16
3x = y-1x + y = 29From the first equation, y = 3x+1Plugging into the second equation:x + 3x + 1 = 294x+1=294x=28x=7plugging that into the second equation,7 + y = 29y = 223(7)=(22)-121 = 21, and the first equation checks as well. ■
35 i do not really no