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The solutions are: x = 4, y = 2 and x = -4, y = -2
20 minus 17 minus 3 minus 2 equals -2
40
There are two equations in the question, both of which are wrong. There is no single fraction which will make both equations correct.
x = 2
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
This cannot be solved. If you have 2 unknowns (a,b) then you must have 2 equations.
10 minus negative 10 equals 20: 10 - (-10) = 20 or rather 10 + 10 = 20. 10- (minus 10) = 20
The solutions are: x = 4, y = 2 and x = -4, y = -2
20 minus 17 minus 3 minus 2 equals -2
30
40
It is: 56 minus 20 = 36
803 - 20 = 783
20 - 3 = 17
There are two equations in the question, both of which are wrong. There is no single fraction which will make both equations correct.
x = 2