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This is a classic calculus problem.

V=s3

dV=3s2 ds

ds = dV/(3s2)

dV = 9 cm3/s

s=4 cm

ds = 9/(3*64) = 3/64 cm/s

SA=6s2

dSA=12s ds

dSA=48*(3/64) cm2/s = 9/4 cm2/s = 2.25 cm2/s

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Q: The volume of a cube is increasing at a rate of 9 cubic centimeters per second How fast is the surface area increasing when the length of an edge is 4 centimeters?
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