speed = frequency × wave_length
→ frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
Wavelength = speed/frequency = 350/640 = 54.7 centimeters (rounded)
The wavelength is halved.
v=f*wavelength v=2*.5 v=1 m/s
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
v = f h, h = lambda = wavelength. f = frequency in Hz v = velocity therefore, v = 1.5 * 440 (the units of v in this case are meters per second).
since v=f(lambda), where v is the speed in metres per second, f is the frequency in hertz and lambda the wavelength in metres , for this question, v= 440 x 1.5=660m/s
This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds. The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.
Question is to be corrected as to find the velocity of the sound waves Formula for velocity of the wave = frequency x wavelength Given frequency = 262 Hz and wavelength = 1.3 m So velocity = 262 x 1.3 = 340.6 m/s
Second Harmonic
It depends: the frequency of what? For example, in the case of a string moving back and forth, that would depend on the length of the string, on its mass, and on its tension.
The first harmonic, is the fundamental frequency, or 550 Hz. The second harmonic would be twice that, or 1100 Hz. The third would be twice that, or 1650 Hz and so on...
Wavelength = velocity of sound in the medium / frequency Here velocity is not given. Let it be 330 m/s So required wavelength = 330/440 = 3/4 = 0.75 m