The wavelength is halved.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
since v=f(lambda), where v is the speed in metres per second, f is the frequency in hertz and lambda the wavelength in metres , for this question, v= 440 x 1.5=660m/s
Its frequency would be higher. Imagine a guitar. When you put your finger higher up the fretboard, you shorten the string essentially. This has the effect of making the note higher
v = f h, h = lambda = wavelength. f = frequency in Hz v = velocity therefore, v = 1.5 * 440 (the units of v in this case are meters per second).
There is no such formula.
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
If the string length doubles, the frequency of the vibrating string decreases by half. This is because frequency is inversely proportional to the length of the string.
No, the fundamental frequency of a vibrating string is determined by its length, tension, and mass per unit length. The length of the string is usually equal to half the wavelength of the fundamental frequency.
The wavelength gets shorter.
Increasing the mass of the guitar string by wrapping a second wire around it will decrease the frequency of the fundamental standing wave because the wave speed remains constant. The wavelength of the standing wave will be longer due to the decrease in frequency.
Wavelength = speed/frequency = 350/640 = 54.7 centimeters (rounded)
The speed of a wave is calculated by multiplying its frequency by its wavelength. In this case, the speed of the waves along the string would be 1.0 meters per second (2.0 Hz * 0.50 m).
The formula to calculate the wavelength of a wave is: wavelength = speed / frequency. Therefore, the wavelength in this case is 4 meters (12 m/s / 3 Hz = 4 m).
If the third harmonic of the string is 540 Hz, then the fundamental frequency of the string is one-third of 540 Hz, which is 180 Hz. When the string is fingered at 60% of its length, the fundamental frequency will decrease because the shorter length results in a higher pitch. To find the new fundamental frequency, you can use the formula: (f = nf_0) where (f_0) is the original fundamental frequency.
speed = frequency × wave_length → frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
The speed of a wave is calculated using the formula v = f * λ, where v is the speed of the wave, f is the frequency, and λ is the wavelength. Plugging in the values given (f = 2.0 Hz, λ = 0.50 m), the speed of the waves along the string is 1.0 m/s.
Question is to be corrected as to find the velocity of the sound waves Formula for velocity of the wave = frequency x wavelength Given frequency = 262 Hz and wavelength = 1.3 m So velocity = 262 x 1.3 = 340.6 m/s