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What happens to the speed of a wave on a string when the frequency is doubled?
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
A wave along a guitar string has a frequency of 440 Hz and wavelength of 1.5 m What is the speed of the wave?
since v=f(lambda), where v is the speed in metres per second, f is the frequency in hertz and lambda the wavelength in metres , for this question, v= 440 x 1.5=660m/s
When a string is plucked at one-third length what happens?
Its frequency would be higher. Imagine a guitar. When you put your finger higher up the fretboard, you shorten the string essentially. This has the effect of making the note higher
A wave along a guitar string has a frequency of 440Hz and a wave length of 1.5m what is the speed of the wave?
v = f h, h = lambda = wavelength. f = frequency in Hz v = velocity therefore, v = 1.5 * 440 (the units of v in this case are meters per second).
What is the formula to calculate the diameter of a string to get the desired Hz if you know the wavelength?
There is no such formula.
What happens to the speed of a wave on a string when the frequency is doubled?
I believe that the speed will remain constant, and the new wavelength will be half of the original wavelength. Speed = (frequency) x (wavelength). This depends on the method used to increase the frequency. If the tension on the string is increased while maintaining the same length (like tuning up a guitar string), then the speed will increase, rather than the wavelength.
What happens if you lower the frequency of a wave on a string?
Lowering the frequency of a wave on a string will result in a longer wavelength and a lower pitch sound.
What happens to frequency if string length doubles?
If the string length doubles, the frequency of the vibrating string decreases by half. This is because frequency is inversely proportional to the length of the string.
When you push down on a string to make it shorter what happens to the wavelength?
The wavelength gets shorter.
Is a string vibrating at the fundamental frequency the length of half the wavelength?
This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds. The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.
If we wrap a second wire around a guitar string to increase its mass what effect does this have on the frequency and wavelength of the fundamental standing wave formed on that string?
Increasing the mass of the guitar string by wrapping a second wire around it will decrease the frequency of the fundamental standing wave because the wave speed remains constant. The wavelength of the standing wave will be longer due to the decrease in frequency.
What is the wavelength of a sound made by a violin string that has a frequency of 640 Hz if the sound is traveling at 350 meters per second?
Wavelength = speed/frequency = 350/640 = 54.7 centimeters (rounded)
Waves with a frequency of 2.0 hertz are generated along a string The waves have a wavelength of 0.50 meters The speed of the waves along the string is?
The speed of a wave is calculated by multiplying its frequency by its wavelength. In this case, the speed of the waves along the string would be 1.0 meters per second (2.0 Hz * 0.50 m).
The speed of a transverse wave in a string is 12 meters per second. If the frequency of the source producing the wave is 3 hertz what is its wavelength?
The formula to calculate the wavelength of a wave is: wavelength = speed / frequency. Therefore, the wavelength in this case is 4 meters (12 m/s / 3 Hz = 4 m).
A tight guitar string has a frequency of 540 Hz as its third harmonic what will be its fundamental frequency if it is fingered at a length of only 60 percent of its original length?
normal fundamental- 180 Hz (open- open) = 540 Hz at 3rd- f at 3rd= 3f' 540 =180 it's wavelength= v/f= 343/180= 1.9 L= 3/2 (wavelength)= 2.85 60% of this = 1.71= new wavelength v= f x wavelength 343/ 1.71= 200 Hz
The wavelength of a wave on a string is 1.2 meters If the speed of the wave is 60 meters per second what is its frequency?
speed = frequency × wave_length → frequency = speed ÷ wave_length = 1.2 m/s ÷ 60 m = 50 Hz.
Waves with a frequency of 2.0 hertz are generated along a string. The waves have a wavelength of 0.50 meters. What is the speed of the waves along the string?
The speed of a wave is calculated using the formula v = f * λ, where v is the speed of the wave, f is the frequency, and λ is the wavelength. Plugging in the values given (f = 2.0 Hz, λ = 0.50 m), the speed of the waves along the string is 1.0 m/s.
