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There are 38 numbers on a roulette wheel and I bet 12 of them. What is the probability of not hitting one of my numbers on 11 consecutive spins?
Jsgconner
If the probability of an event will occur is p, then the probability that it will occur in n trials is pn.(That's p raised to the n power). So if you bet on 12 numbers, then (38-12=26) numbers are empty. The probability of the ball landing on one of these empty numbers is 26/38. So (26/38)^11 = 0.01538, which is about 1.538 % or a 1 in 65 chance.
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