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Q: There are 3 stars shaded and 4 stars and there's 7 stars in all what is the fraction?

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3/7 * 100 = 42.857% of the stars are shaded.4/7 * 100 = 57.143% are not shaded.

A whole

whole number

-- Look at the picture, count how many squares are shaded, write down the number. -- Look at the picture again, count how many squares there are all together, whether they're shaded or not shaded. Write down the number. -- Make a fraction. Put the first number on top, put the second number on the bottom. (-- Reduce the fraction to lowest terms, it necessary, and if you know how to do that.)

Draw as many rectangles as the whole number you are multiplying by. Then, draw the fraction you are multiplying by in all of the rectangles. Shade in the top number in the fraction [numerator] in your rectangles. Count all the shaded in parts of all your rectangles. Leave the bottom number of your fraction [denominator] the same and put the number you got when you added the shaded parts of the rectangles on top as your denominator of the fraction. That is your answer!

Approximately 90% of all stars are on the main sequence.

About 90% of all the stars you can see will be on the main sequence.

because theres 2 more states added to it then they all represent the states in us

Count all the squares then count the shaded squares put the shaded number at the top and the number of all squares at the bottom so it might look like this ⅜ 8 is the total and 3 is the number of shaded squares

No. Only very big stars go supernova, and out of those, only a fraction turn into black holes.

50%

All of the symbols are shaded.

Move the knight until all the squares are shaded (the horse has been on all of them)

no,but all stars have a name

All suns are stars.

Actually, a linear inequality, such as y > 2x - 1, -3x + 2y < 9, or y > 2 is shaded, not a linear equation.The shaded region on the graph implies that any number in the shaded region is a solution to the inequality. For example when graphing y > 2, all values greater than 2 are solutions to the inequality; therefore, the area above the broken line at y>2 is shaded. Note that when graphing ">" or "=" or "

cheerforce all stars is a cheerleading team in rancho cucamoga,ca ps: fierce all stars hates cherrforce all stars

Yes, a sword with a eagle handle and tribal background. All black and shaded.-Shocker

Because all the gas could come out

All stars and galaxies are in the universe.

Multiply all the numerators together and then multiply all the denominators together

Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.Kerry, with 49 All-stars up to 2012.

All of them?? well theres no site NOO Cross out "All of them??" ---- ---- All of them??

theres not a code idiot.......jk but srry theres no no code theres not a code idiot.......jk but srry theres no no code

no it was all a hoax to prove it theres no wind on the moon and the flag was moving and there was shadows in pictures and there is no light and there is no stars in the pictur and there is stars in the sky The same old arguments that have been disproved time and time again. Yes he was.