translation of graphs , try that :)
help me please
That would be a pleasant diversion. Sadly, however,you've neglected to give us the "given" set.
There are 22 ways to make change from a dollar using nickels, dimes, and quarters. 1. 4 q 2. 10 d 3. 20 n 4. 2 q , 5 d 5. 3 q , 2 d , 1 n 6. 1 q , 7 d, 1 n 7. 9 d, 2 n 8. 8 d, 4 n 9. 7 d, 6 n 10. 6 d , 8 n 11. 5 d , 10 n 12. 4 d , 12 n 13. 2 d , 16 n 14. 1 d , 18 n 15. 5 n , 3 q 16. 3 n , 1 q , 6 d 17. 7 n , 1 q , 4 d 18. 9 n , 1 q , 3 d 19. 11 n , 1 q , 2 d 20. 13 n , 1 q , 1 d 21. 14n , 3 d 22. 15n , 1 q
Let's suppose you mean How many vertices does a nonahedron have? And the answer is, It depends. A nonahedron is a solid with nine faces. There is no regular nonahedron (look up "Regular solid" anywhere, say on Wikipedia). You could make a nonahedron bytaking a cube (6 square faces, 12 vertices) and slicing off 3 of the vertices to add 3 triangular faces (and making their adjacent original faces no longer square); this solid has 16 verticestaking a regular octahedron (8 triangular faces, 6 vertices) and slicing off one vertex to add one square face (the four adjacent original faces are now trapezoids): 9 verticesshaving down 5 of the edges to add 5 long narrow faces... and I can't visualize this one well enough to count the verticesor slicing off all 4 vertices (adding 4 small triangular faces and making the original faces hexagonal) and shaving one edge (adding a long rectangular face and changing the faces at the ends of the original edge from small triangles to trapezoids): 14 vertices, if I've got it right.taking a tetrahedron (4 faces, 6 edges, 4 vertices) andor countless other ways, yielding many different counts of vertices. ... Well, I'm sure they could be counted, but I'm not about to do it now.
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