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Q: Three consecutive integers that have a sum of 96?

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Add them up. 90, 91, 92, 93, 94, 95, 96, 98, 99, 100

There are 96 heads, so 96 animals. If all were horses, that would be 4 x 96 = 384 legs, but there are only 313 legs, which means there are 384-313 = 71 legs short or 71 cows and 25 horses. Mathematically, let x = horses and y = cows x + y = 96 4x + 3y = 313 multiply first equation by 4: 4x + 4y = 384 4x + 3y = 313 subtract equations y = 71 = cows x = 25 = horses

96

8 divided by 96 equals 12.

The GCF of 56 and 96 is 8.

Related questions

31, 32, 33

31 32 33

?

The numbers are 31, 32 and 33.

If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.

31, 32 and 33

-31, -32, -33

The integers are 47 and 49.

Average is 96/3 ie 32 so integers are 30, 32 and 34.

They are odd consecutive integers: 21, 23, 25 and 27.

The integers are -98 and -96.

31, 32, 33

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