answersLogoWhite

0

If three consecutive integers have the sum of 96, then the problem can be expressed with the equation...

N + (N+1) + (N+2) = 96

...Simplify that and solve and you get...

3N + 3 = 96

3N = 93

N = 31

... so the three integers are 31, 32, and 33.

User Avatar

Wiki User

15y ago

What else can I help you with?