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If three consecutive integers have the sum of 96, then the problem can be expressed with the equation...

N + (N+1) + (N+2) = 96

...Simplify that and solve and you get...

3N + 3 = 96

3N = 93

N = 31

... so the three integers are 31, 32, and 33.

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Q: Three consecutive integers that have the sum of 96?
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