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What does the time taken for a simple pendulum to swing to and fro in one cycle call?
The time taken for a simple pendulum to swing to and fro in one cycle is called the period of the pendulum.
What is the period of a pendulum that takes 3 seconds to move forward and another 3 seconds to come back'?
The period of the pendulum is the time taken for one complete back-and-forth motion. In this case, since the pendulum takes 3 seconds to move away and 3 seconds to come back, the total time for one full cycle is 6 seconds. Therefore, the period of the pendulum is 6 seconds.
Does amplitude effect the period of a pendulum?
No, the amplitude of a pendulum (the maximum angle it swings from the vertical) does not affect the period (time taken to complete one full swing) of the pendulum. The period of a pendulum depends only on its length and the acceleration due to gravity.
How do you illustrate graph of a simple pendulum?
To illustrate the graph of a simple pendulum, you can plot the displacement (angle) of the pendulum on the x-axis and the corresponding period of oscillation on the y-axis. As the pendulum swings back and forth, you can record the angle and time taken for each oscillation to create the graph. The resulting graph will show the relationship between displacement and period for the simple pendulum.
What is the length of a pendulum of period 1.6 seconds?
The length of a pendulum with a period of 1.6 seconds can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length, and g is the acceleration due to gravity. Solving for L, the length of the pendulum is approximately 1.02 meters.
What is the frequency of oscillation of a simple pendulum which makes 50 oscillations in 24.4 seconds?
The period of oscillation is the time taken for one complete oscillation. The frequency of oscillation, f, is the reciprocal of the period: f = 1 / T, where T is the period. In this case, the period T = 24.4 seconds / 50 oscillations = 0.488 seconds. Therefore, the frequency of oscillation is f = 1 / 0.488 seconds ≈ 2.05 Hz.
What is the time period of a pendulum which oscillates 40 times in 4 seconds?
The time period of the pendulum is the time taken for one complete oscillation. Since the pendulum oscillates 40 times in 4 seconds, the time period of each oscillation is 4 seconds divided by 40, which equals 0.1 seconds.
Does the period of simple pendulum depend on the mass of the bob?
Not in the theoretical world, in the practical world: just a very little. The period is determined primarily by the length of the pendulum. If the rod is not a very small fraction of the mass of the bob then the mass center of the rod will have to be taken into account when calculating the "length" of the pendulum.
What will happen to time period of simple pendulum if taken to satellite?
A simple pendulum will not swing when it's aboard a satellite in orbit. While in orbit, the satellite and everything in it are falling, which produces a state of apparent zero gravity, and pendula don't swing without gravity.
Does the distance a pendulum travels decrease with each arc?
if by arc you mean the "Period" of the pendulum then yes, it does: with each revolution the period of the pendulum (the time taken to swing back and forth once) does decrease.
How do you calculate the acceleration due to gravity using a simple pendulum?
The acceleration due to gravity can be calculated using a simple pendulum by measuring the period of oscillation (time taken for the pendulum to complete one full swing) and the length of the pendulum. The formula to calculate acceleration due to gravity is: g = 4π²L / T², where g is acceleration due to gravity, L is the length of the pendulum, and T is the period of oscillation.
Will a pendulum time period increase or decrease when taken to the top of the mountain?
The time period of a pendulum will increase when taken to the top of a mountain. This is because the acceleration due to gravity decreases at higher altitudes, resulting in a longer time for the pendulum to complete each oscillation.
