Area of a quadrant = 0.5x(side A + opposite side B)x0.5x(side C + opposite side D) Area of a quadrant = 0.5x(side A + opposite side B)x0.5x(side C + opposite side D)
Area of quadrant: (Radius X Radius X pi(3.14 or 22/7)) divided by 4
0.5*3.141593*r + 2*r
perimeter of what quadrant?
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
It is the sum of its 4 sides which is its perimeter.
In a circle of radius, r, perimeter of quadrant = pi*r/2 + 2r = r*(pi/2 + 2)
that would be a squere xD
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Pi / 5 would be in Quadrant I.
If you know the perimeter, there is no need to find it again.
Here's how to do that: 1). Find its length. 2). Find its perimeter. 3). Divide (its length) by (its perimeter). The quotient is the ratio of its length to its perimeter.
It is not possible. A quadrant extends infinitely far in two directions and so has no centre.
To find the perimeter you add and to find the area we multiply.