Pi / 5 would be in Quadrant I.
Chat with our AI personalities
9.3333
On a Unit Circle, the cosine is the x coordinate of the point on the circle represented by an angle. Angles greater than 90° (pi/2 radians) and less than 270° (3*pi/2 radians) are to the left of the y-axis, so x is negative. Quadrant I is the upper right quadrant (x positive, y positive) 0° < ɵ < 90° Quadrant II is the upper left quadrant (x negative, y positive) 90° < ɵ < 180° Quadrant III is the lower left quadrant (x negative, y negative) 180° < ɵ < 270° Quadrant IV is the lower right quadrant (x positive, y negative) 270° < ɵ < 360°
Assuming that 12 in refers to the radius, then the area is 113.04 square inches.
2 pi / 2 = pi.
cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2