9.3333
On a Unit Circle, the cosine is the x coordinate of the point on the circle represented by an angle. Angles greater than 90° (pi/2 radians) and less than 270° (3*pi/2 radians) are to the left of the y-axis, so x is negative. Quadrant I is the upper right quadrant (x positive, y positive) 0° < ɵ < 90° Quadrant II is the upper left quadrant (x negative, y positive) 90° < ɵ < 180° Quadrant III is the lower left quadrant (x negative, y negative) 180° < ɵ < 270° Quadrant IV is the lower right quadrant (x positive, y negative) 270° < ɵ < 360°
Assuming that 12 in refers to the radius, then the area is 113.04 square inches.
cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2
Pi is infinite. The current number of digits calculated is over ten-trillion. If you want to find a pretty good estimate, divide 22 by 7.
Pi / 5 would be in Quadrant I.
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).
If the radius of the circle is r, then the area of the quadrant is 0.25*pi*r^2
No, it is not.
No
Circumference of a circle = 2 * pi * r pi = 3.1415926535897932384626433832795 r= radius of circle Hence Circumference of a Quadrant = 2 * pi * r / 4 = pi * r / 2 = 0.5 * pi * r For more accurate value of pi, please refer: http://en.wikipedia.org/wiki/Pi
sin pi/2 =1 sin 3 pi/2 is negative 1 ( it is in 3rd quadrant where sin is negative
(radius x radius x pi) divided by 4
8.3 Radians? is in the second quadrant. 8.3/pi*180 is about 115. 115 is in the second quadrant.
In a circle of radius, r, perimeter of quadrant = pi*r/2 + 2r = r*(pi/2 + 2)
If you the radius of the circle is r then the perimeter of a quadrant = r*(2 + pi/2).