sir ,
what is perfect no?
Yes
Enter "java -version" into a terminal. If Java is installed, it will tell you the version number. If it is not installed, it will say "command not found."
Java Development Kits are best found on the Java website. There are a number of programmes that can be downloaded. It is also possible to get Java Development Kit downloads from the Oracle website.
If by system number you mean the version number of the Java language on the client computer, you can useSystem.getProperty("java.version"); .Or, if you want the Java virtual machine version number you can use System.getProperty("java.vm.version"); .Finally, if you want the version number of the operating system, you can use System.getProperty("os.version"); .
Math.sqrt(number) function is used to find the square root of a number.. try it
You can use the Math.sqrt() method.
There are a number of sites that list the many uses of Java applications. The official Java website is one of these sites. Alternatively, one may also find this information at the web domain DynamicDrive.
That means that Java is fairly strict about data types.
There are several sites online where one can download the Java plugin such as Java, Oracle, Cnet, and Microsoft. One can find their current version of Java by visiting the Java Tester website.
Open cmd and type java
In JavaScript, a "strong number" (or "Armstrong number") for a given number of digits is a number that is equal to the sum of its own digits each raised to the power of the number of digits. For example, 153 is a strong number because it has three digits, and (1^3 + 5^3 + 3^3 = 153). To determine if a number is a strong number, you can convert it to a string to access each digit, calculate the sum of the digits raised to the appropriate power, and then compare it to the original number.
There are a number of websites which specialise in Java tips and how-to guides. Websites from AvaJava, CSC and JavaMex are just some of the websites available as well as blogs such as that from 'Javarevisited'.