To input an integer array and print the first two maximum numbers?

Answer 1

Here is an example for type double:

#include

using std::cin;
using std::cout;
using std::endl;

double maxFirst(const double data[], int index);
double maxSecond(const double data[], int index, double maxNumber1);
double sum(double max1, double max2);

int main()
{
const int arraySize = 10;
double myArray[arraySize] ={0.0};

cout << "Enter numbers: " << endl;
for (int i(0); i < arraySize; i++)
{
cout << "Enter " << (i + 1) << " element: ";
cin >> myArray[i];
}

cout << "Your array is: ";
for (int k = 0; k < arraySize; k++)
{
cout << endl << myArray[k];
}

double max1 = maxFirst(myArray, arraySize);
double max2 = maxSecond(myArray, arraySize, max1);

cout << endl << "First biggest number is: " << max1;
cout << endl << "Second biggest number is: " << max2;
cout << endl << "Sum of these two is: " << sum(max1, max2) << endl;

system("PAUSE");
return 0;
}

double maxFirst(const double data[], int index)
{
double maxNumber1 = data[0];
for (int i = 0; i < index; i++)
{
if (maxNumber1 < data[i])
{
maxNumber1 = data[i];
}
}

return maxNumber1;
}
double maxSecond(const double data[], int index, double maxNumber1)
{
double maxNumber2 = data[1];
for (int j = 0; j < index; j++)
{
if (data[j] == maxNumber1)
{
continue;
}
else if (maxNumber2 < data[j])
{
maxNumber2 = data[j];
}
}

return maxNumber2;
}
double sum(double max1, double max2)
{
return (max1 + max2);
}