How much does it cost? Will it fit in the space provided? Is cooling for it provided? When can it be delivered? Does it need provision for tapping for minor voltage changes? Does it need provision for remote monitoring? Voltage variation with load. Conformance with applicable standards. Frequency. A TRANSFORMER IS A PASSIVE DEVICE SO YES THE INPUT VOLTAGE IS NECCESSARY FREQUENCY OF OPERATION THE KVA OUTPUT IS ALL THAT YOU NEED.
Resistors could be used if you can find resistors with a high enough wattage rating to dissipate the heat that they will generate. Your best bet is to purchase a voltage adapter. The adapter is just a transformer that steps down the voltage from 220 to 110 volts. Locate on the hair dryer what the wattage draw is and then match the transformer (adaptor) to that wattage output.
The rating is about 1500W. This is for both the input and the output. Output voltage is usually 2,000 volts. Divide watts by input volts to get input current. And divide watts by output voltage to get output current. -Joe
To answer this question some values must be stated. The voltage and amperage must be known to find the wattage. W = A x V.
A transformer has a rating that is usually expressed in KVA. This is approximately a wattage rating. It is not dangerous but it can be the cause of some concern. An appliance has a set current that is draws. This current times the voltage is the appliance's wattage. The same goes for the transformer. It only has a certain capacity to supply a specific current that is governed by its KVA (watts). Driving the transformer beyond its rated capacity tends to heat the transformer beyond its working temperature. If left in this over current draw the transformer's windings insulation will break down and the windings will short circuit. This is usually the end of a working transformer. So short answer, more watts (amps) from appliance equals burned out transformer.
To answer this question a supply voltage must be stated. Also the wattage of the lamps is needed.
Resistors could be used if you can find resistors with a high enough wattage rating to dissipate the heat that they will generate. Your best bet is to purchase a voltage adapter. The adapter is just a transformer that steps down the voltage from 220 to 110 volts. Locate on the hair dryer what the wattage draw is and then match the transformer (adaptor) to that wattage output.
I am going to say NO.... Although it would be possible if you purchase a transformer (with the correct wattage rating) to reduce the voltage from 480 to 120.
It outputs high voltage so that the magnetron (which is recieving the 2000v the Microwave transformer produces) can emit microwaves and it will cook the food but if fed lower voltage it is like a lower wattage it will cook slower
If the load current is too high, the power lost in the transformer windings will be too high and it will overheat. If the voltage is excessive, the power lost in eddy currents in the magnetic core will be too high and it will overheat.
That depends on the voltage V. Wattage P = amperage A times voltage V.
It is either a short in (1 or more) of the windings (if its multi-phase) or the applied voltage was too high. What is the application, size (wattage), voltage, a number of phases for this Xfmr? I might be able to help you troubleshoot it further with this information.AnswerIt depends on what you mean by 'blown'! Do you mean the primary fuse has operated? If so, then it's likely the transformer's load has exceeded the capacity of the transformer.
No, the rating of the transformer, in watts, is the maximum amount of energy that can be safely drawn from the device. Any wattage load up to that limit is safe to connect as long as the voltage is correct to the load.
Wattage= current*voltage*power factor. Wattage=VI Cos(@)
The rating is about 1500W. This is for both the input and the output. Output voltage is usually 2,000 volts. Divide watts by input volts to get input current. And divide watts by output voltage to get output current. -Joe
To answer this question some values must be stated. The voltage and amperage must be known to find the wattage. W = A x V.
wattage is nothing but power product of current and voltage p=v*i
Wattage, you mean power. Power = V * I. V - the voltage and I the current.