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Suppose the circle meets QR at A, RP at B and PQ at C.

PQ = PR (given)

so PC + CQ = PB + BR.

But PC and PB are tangents to the circle from point P, so PC = PB.

Therefore CQ = BR

Now CQ and AQ are tangents to the circle from point Q, so CQ = AQ

and BR and AR are tangents to the circle from point R, so BR = AR

Therefore AQ = AR, that is, A is the midpoint of QR.

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Q: Triangle pqr is an isosceles triangle in which pq equals pr equals 5cm it is circumscribed about a circle prove that qr is bisected at point of contact?
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