false
We know that a prime number is a positive integer greater than 1, whose divisors are 1 and itself. We know that the only even prime number is 2. That means that all other prime numbers are odd numbers.We know that when we add two odd numbers the result is an even number, which are not prime numbers (expect 2, and 2 = 1 + 1 where 1 is odd but is neither prime nor composite). Thus adding two odd prime numbers cannot give us another prime number.We show that the conclusion follows from the premise:Assume that r = p + q where all r, p and q are prime numbers, then we have that r is either even or not:If r is even then r is at least 4 (the smallest number which is the sum of two primes) and thus not a prime number. This contradicts the assumption that r is a prime number, and therefore we conclude that r is not even.If r is odd then either p or q must be odd and the other one must be even, since both p and q are prime numbers one of them must be 2 (the only even prime number).2 + 3 = 5, 2 + 17 = 19, are examples of such numbers.
whats the number wise position of Gandhi R. as prime minister of India
The number 41 is a prime number. A prime number has only 2 factors which are 1 and itself. Composite numbers are everything else except 1 and 0. 1 and 0 are neither prime, nor composite.To test a number to find out if it is prime or composite, try dividing it by the first few prime numbers:41 ÷ 2 = 20 r 141 ÷ 3 = 13 r 241 ÷ 5 = 8 r 141 ÷ 7 = 5 r 6We don't have to test 4 or 6, since they are both divisible by 2. The divisor (7) is now larger than the result (5 remainder 6), so we can stop. 41 is prime.
1 and 79 because it's a prime number
They are itself and one because 13 is a prime number
It depends on the value of r, which you have not specified.
Any prime number to the eighth power, like 256 or 6561.
Yes, it is always. Assume temporarily that the product of two prime numbers is not always composite. This implies that that at least one product of prime numbers is also prime. Now, say two different prime numbers p and q, when multiplied, equal r. If r is a prime number, then r's only positive factors are 1 and r. But 1 is not a prime number. This contradicts that both p and q are prime (because either p or q MUST be 1). Therefore, the product of two prime numbers is always composite.
We know that a prime number is a positive integer greater than 1, whose divisors are 1 and itself. We know that the only even prime number is 2. That means that all other prime numbers are odd numbers.We know that when we add two odd numbers the result is an even number, which are not prime numbers (expect 2, and 2 = 1 + 1 where 1 is odd but is neither prime nor composite). Thus adding two odd prime numbers cannot give us another prime number. We show that the conclusion follows from the premise:Assume that r = p + q where all r, p and q are prime numbers, then we have that ris either even or not:* If r is even then r is at least 4 (the smallest number which is the sum of two primes) and thus not a prime number. This contradicts the assumption that r is a prime number, and therefore we conclude that r is not even. * If ris odd then either p or q must be odd and the other one must be even, since both p and q are prime numbers one of them must be 2 (the only even prime number). 2 + 3 = 5, 2 + 17 = 19, are examples of such numbers. See http://en.wikipedia.org/wiki/Twin_prime for more.
Only itself and one because 2 is a prime number
The term "main prime factor" is interpreted as "prime factor" (all prime factors are main prime factors).Since 73 is prime, your question can be generalized to:What are the prime factors of a prime?You may know that all numbers have a unique factorization in primes. This is a theorem. What you need is the definition of a prime number to prove this theorem in the first place.A number which has only two divisors, namely 1 and the number itself, is called prime. Hence, by definition, the prime factors of a prime are the prime and 1.So your question is trivial, asking to recognize 73 to be a prime. The answer is 73.The question of how to determine that 73 is prime is a good one.Basically you can prove it by noting that it can not be divided by any prime smaller than 73^(1/2) < 8:73 / 2 = 36 R 1 -- the expression n R m means n with remainder m73 / 3 = 24 R 173 / 5 = 14 R 373 / 7 = 10 R 3Hence (since 2, 3, 5 and 7 are all primes smaller than 8), 73 is prime.2 is prime (there is not integer between 1 and 2)3 is prime, since 3/2 = 1 R 15 is prime, since 5/2 = 2 R 1 (we do not need to test with 3, because 5 < 3^2)7 is prime, since 7/2 = 3 R 1 (we do not need to test with 3, because 7 < 3^2)
25 is not a prime number, it is a composite number, because it can be multiplied by 5 to get 25. A prime number can only be divisible by itself and 1.25 is a composite number like every number greater than 5 that ends with a 5.No, it is divisible by 5.