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Q: Tthe probability that two heterozygous parents for widow's peak will have a child with a straight hairline is what percent?
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What was the probability that two heterozygous parents would have an offspring that produced round seeds?

25%


What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?

3:4 or 75%


What is probability that two heterozygous parents would have an offspring that produced round seeds?

It is a 75% chance that the seeds will be round.


What is the probability that the children will be heterozygous?

Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.


If purple flower color is dominant over white flower color how can two purple flowered parents produce while flowered offspring?

It can happen when both parents are a heterozygous


What is probability that wto heterozygous parents would have an offspring that produced round seeds?

75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.


Which of the following calculations require that you utilize the addition rule?

Calculate the probability of a child having either sickle-cell anemia or cystic fibrosis if parents are each heterozygous for both.


What is the probability that two heterozygous parents would have an offspring that produced round seeds?

The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.


If both heterozygous parents are carriers of a recessive allele for phenylketonuria the probability that a given child of these parents will have PKU is?

Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%


Will the child have a continuos hairline?

That depends on the genes of the parents.


Can you give me a sentence using the word heterozygous?

Heterozygous means inheriting different genes from your parents. That is a heterozygous trait, not a homozygous one.


If children with blood group O and a what could be the blood group of parents?

both parents could be A heterozygous or one A heterozygous and the other O