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3:4 or 75%
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
It depends upon what the parents were. If both parents were dwarf and white, then it is 100% If both parents were heterozygous for both traits, then it is 1/16. If either parent were homozygous tall and colored, then it is 0. Make a Punnett Square to get all of the probabilities if you know the genotypes of the parents.
Genotype is used to determine the probability of having specific offspring from two known parents.
It would depend on the parents' genes and age. Globally, the probability is approx 0.483
25%
3:4 or 75%
It is a 75% chance that the seeds will be round.
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
It can happen when both parents are a heterozygous
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
Calculate the probability of a child having either sickle-cell anemia or cystic fibrosis if parents are each heterozygous for both.
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
Pp x Pp yields PP, Pp, Pp, pp. PP is the only genotype which will cause the phenotypic expression of the gene - symptoms of PKU. Therefore the probability is 1/4 or 25%
That depends on the genes of the parents.
Heterozygous means inheriting different genes from your parents. That is a heterozygous trait, not a homozygous one.
both parents could be A heterozygous or one A heterozygous and the other O