A deck of cards consists of 52 cards.
Each card is available four times.
That makes 13 diffent card types.
Four different cards are worth 10 points: 10, Jack, Queen, King.
That means that 4x4 Cards out of 52 are worth ten.
That are about 30% (30/100).
Two tens in a row have the expectation of 30%x30% which is about 9%.
A probability density function assigns a probability value for each point in the domain of the random variable. The probability distribution assigns the same probability to subsets of that domain.
When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens, kings, or aces get discarded, but increases when other cards get discarded. This change is unpredictable, but its expected value is 0; this is a complicated concept to explain, but it means that on average, the probability will go up as much as it goes down. Also, the probability is still 32/663 at any point in the game if you have no information whatsoever about what cards came up before: if you forgot every card you saw, or if you just joined the game.
The value of 4800 is 4800 and probability has nothing to do with it.
The probability is 0.
Yes- the highest probability value is the mode. Let me clarify this answer: For a probability mass function for a discrete variables, the mode is the value with the highest probability as shown on the y axis. For a probability density function for continuous variables, the mode is the value with the highest probability density as shown on the y-axis.
The probability of drawing 3 cards, all with the value of 9, from a standard 52 card deck, is ~0.018%.
A probability density function assigns a probability value for each point in the domain of the random variable. The probability distribution assigns the same probability to subsets of that domain.
The answer depends on the set of values that the cards can have , and how many cards there are for each value.The answer depends on the set of values that the cards can have , and how many cards there are for each value.The answer depends on the set of values that the cards can have , and how many cards there are for each value.The answer depends on the set of values that the cards can have , and how many cards there are for each value.
When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens, kings, or aces get discarded, but increases when other cards get discarded. This change is unpredictable, but its expected value is 0; this is a complicated concept to explain, but it means that on average, the probability will go up as much as it goes down. Also, the probability is still 32/663 at any point in the game if you have no information whatsoever about what cards came up before: if you forgot every card you saw, or if you just joined the game.
The value of 4800 is 4800 and probability has nothing to do with it.
The probability is 0.
It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.It is a variable that can take a number of different values. The probability that it takes a value in any given range is determined by a random process and the value of that probability is given by the probability distribution function.
There is a 1 in 52 chance that the first card drawn in a standard, shuffled 52 card deck, will have a value of 7.
Zero is the smallest probability.
Yes- the highest probability value is the mode. Let me clarify this answer: For a probability mass function for a discrete variables, the mode is the value with the highest probability as shown on the y axis. For a probability density function for continuous variables, the mode is the value with the highest probability density as shown on the y-axis.
The answer i got was 1 3/26 The cards are red or black, so the chance of getting black is 1/2 The cards less than nine is 1-8. There are 4 of each value, so 8 cards times 4 suits equals 32. The chance of getting a card less than nine is 32/52, or 8/13 1/2 plus 8/13 is 13/26 plus 16/ 26, which equals 29/26, or 1 3/26 That is how i solved it.
The expected value is the average of a probability distribution. It is the value that can be expected to occur on the average, in the long run.