When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens, kings, or aces get discarded, but increases when other cards get discarded. This change is unpredictable, but its expected value is 0; this is a complicated concept to explain, but it means that on average, the probability will go up as much as it goes down. Also, the probability is still 32/663 at any point in the game if you have no information whatsoever about what cards came up before: if you forgot every card you saw, or if you just joined the game.
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The odds of being dealt three suited sevens in a six-deck game are approximately 63,000 to 1. [Source: Arnold Snyder, "The Big Book of Blackjack" p205] The odds of being dealt three sevens (not suited) is somewhat worse than 500 to 1 (considering that casinos frequently offer the payout of 500 to 1 for players receiving three unsuited 7s in the "Super Sevens" side bet).
If only one card is dealt randomly from a deck of cards, the probability is 1/52.
Probability of 2 of clubs = 1/52 or 0.0192.
It is 0.000404
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.