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Let θ be the angle between the two vectors A and B such that, |A| = |B|.

Therefore,

R 2 = A 2 + B 2 + 2AB cosθ

=> A 2 = A 2 + A 2 + 2(A)(A) cosθ [since, |A| = |B| = |R|]

=> A 2 = 2A 2 + 2A 2 cosθ

=> cosθ = -1/2

=> θ = 60 degrees

negative sign is not considered becaus eof the modulus sign

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Q: Two equal forces have their resultant equal to either at what angle are they inclined?
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